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	<title>Comments on: 0,3х-1,1(4-2 х)&#038;gt;7,5х+1,6</title>
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		<title>By: Бобров Анатолий</title>
		<link>https://ukrreferat.com/questions/0-3h-1-1-4-2-h-amp-gt-7-5h-1-6#comment-184</link>
		<dc:creator><![CDATA[Бобров Анатолий]]></dc:creator>
		<pubDate>Fri, 19 Apr 2019 00:00:55 +0000</pubDate>
		<guid isPermaLink="false">https://ukrreferat.com/?p=160428#comment-184</guid>
		<description><![CDATA[
&lt;p&gt;0,3х - 1,1 * (4 - 2 х) &#062; 7,5х + 1,6;&lt;/p&gt;
&lt;p&gt;0,3х - 1,1 * 4 + 1,1 * 2х &#062; 7,5х + 1,6;&lt;/p&gt;
&lt;p&gt;0,3х - 4,4 + 2,2х &#062; 7,5х + 1,6;&lt;/p&gt;
&lt;p&gt;-1,6 - 4,4 &#062; 7,5х - 0,3х - 2,2х;&lt;/p&gt;
&lt;p&gt;-6 &#062; 7,5х - 2,5х;&lt;/p&gt;
&lt;p&gt;-6 &#062; 5х;&lt;/p&gt;
&lt;p&gt;5х &#060; -6;&lt;/p&gt;
&lt;p&gt;х &#060; -6 : 5;&lt;/p&gt;
&lt;p&gt;х &#060; - &lt;sup&gt;6&lt;/sup&gt;/&lt;sub&gt;5&lt;/sub&gt;;&lt;/p&gt;
&lt;p&gt;-&lt;sup&gt;6&lt;/sup&gt;/&lt;sub&gt;5&lt;/sub&gt; = - 1&lt;sup&gt;1&lt;/sup&gt;/&lt;sub&gt;5&lt;/sub&gt; = - 1&lt;sup&gt;2&lt;/sup&gt;/&lt;sub&gt;10&lt;/sub&gt; = -1,2&lt;/p&gt;
&lt;p&gt;х &#060; -1,2.&lt;/p&gt;
&lt;p&gt;Ответ: х &#060; -1,2.&lt;/p&gt;
]]></description>
		<content:encoded><![CDATA[<p>0,3х &#8211; 1,1 * (4 &#8211; 2 х) &gt; 7,5х + 1,6;</p>
<p>0,3х &#8211; 1,1 * 4 + 1,1 * 2х &gt; 7,5х + 1,6;</p>
<p>0,3х &#8211; 4,4 + 2,2х &gt; 7,5х + 1,6;</p>
<p>-1,6 &#8211; 4,4 &gt; 7,5х &#8211; 0,3х &#8211; 2,2х;</p>
<p>-6 &gt; 7,5х &#8211; 2,5х;</p>
<p>-6 &gt; 5х;</p>
<p>5х &lt; -6;</p>
<p>х &lt; -6 : 5;</p>
<p>х &lt; &#8211; <sup>6</sup>/<sub>5</sub>;</p>
<p>&#8211;<sup>6</sup>/<sub>5</sub> = &#8211; 1<sup>1</sup>/<sub>5</sub> = &#8211; 1<sup>2</sup>/<sub>10</sub> = -1,2</p>
<p>х &lt; -1,2.</p>
<p>Ответ: х &lt; -1,2.</p>
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